1.25x^2+2x-0.25=0

Solution for 1.25x^2+2x-0.25=0 equation:

1.25x^2+2x-0.25=0

a = 1.25; b = 2; c = -0.25;
Δ = b2-4ac
Δ = 22-4·1.25·(-0.25)
Δ = 5.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{5.25}}{2*1.25}=\frac{-2-\sqrt{5.25}}{2.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{5.25}}{2*1.25}=\frac{-2+\sqrt{5.25}}{2.5}
$